o brutarie a distribuit 2000 de paini in patru magazine.la primu magazin a trimis 3 lazi a cate 86 de paini,la al doilea cu 186 mai multe iar restul in mod egal la celeleate doua magazine.cate paini a primit fiecare magazin?"
primul magazin: 86x3=258 paini al doilea magazin: 258+186=444 paini 2000-(444+258)=1298n paini pentru magazinele 3 si 4 magazinul 3: 1298:2=649 paini magazinul4: 649 paini
3*86=258 paini la primul magazin 186+258=444 paini la al 2-lea magazin 2 000-702=1298paini a ramas la cele 2 magazine 1298:2=649paini a primit al treilea magazin si tot 649a primit si al patrulea proba 258+444+649+649= 702+1298=2 000
