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2[(2×-1)-3(4×-1)]=3[(3×+2)-1]-(19×+13)= AJUTATIMA VA ROG

Răspuns :

   
[tex]2[(2x-1)-3(4x-1)]=3[(3x+2)-1]-(19x+13) \\ 2[2x-1-12x+3]=9x+6-3-19x-13 \\ 2[-10x+2]=-10x-10 \\ -20x+4=-10x-10 \\ -20x+10x =-10-4 \\ -10x =-14 \\ x= \frac{-14}{-10}= \boxed{\frac{7}{5}} = \boxed{1\frac{2}{5}}= \boxed{1,4}[/tex]



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