Răspuns :
15/(2x-1) ∈N => (2x-1)|15 <=> (2x-1) {-1;1;-15;15}
1) 2x-1= -1 => 2x= 0 <=> x=0
2) 2x-1= 1 => 2x=2 <=> x=1
3) 2x-1= -15 <=> 2x= -14 <=> x= -7∉ N
4) 2x-1= 15 <=> 2x =16 <=> x= 8
x={0,1,8}
1) 2x-1= -1 => 2x= 0 <=> x=0
2) 2x-1= 1 => 2x=2 <=> x=1
3) 2x-1= -15 <=> 2x= -14 <=> x= -7∉ N
4) 2x-1= 15 <=> 2x =16 <=> x= 8
x={0,1,8}