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Denisadenny4341
a fost răspuns

descompus in produsi de factori :(4x+1)²-(2x+3)²este:

Răspuns :

Miky93
(4x+1)² -(2x+3)²=[(4x+1)-(2x+3)][(4x+1)+(2x+3)]=

=(4x+1-2x-3)(4x+1+2x+3)=

=(2x-2)(6x+4)=

=2(x-1)(3x+2)
=(4x+1+2x+3)[(4x+1)-(2x+3)=(6x+4)(4x+1-2x-3)=(6x+4)(2x-2)=2(3x+2)*2(x-1)=4(3x+2)(x-1). 
am folosit formula a^2-b^2=(a+b)(a-b) unde a=4x+1, iar b=2x+3