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Rico2015
a fost răspuns

Daca x+2y=17 si y-3z=4 atunci calculati 2)x+3y-3z b)2x+5y-3z c)(3x+6y) + (2y-6z) d) (2x+4y)*(x+4y-6z)

Răspuns :

Nonim
x+3y-3z=(x+2y)+(y-3z)=17+4=21

(3x+6y)+(2y-6z)=3(x+2y)+2(y-3z)=3•17+2•4=51+8=59

(2x+4y)(x+4y-6z)=2(x+2y)•[(x+2y)+(2y-6z)]=2•17•[17+2(y-3z)]=34•(17+2•4)=34•(17+8)=34•25=850

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