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a fost răspuns

Daca x+2y=17 si y-3z=4 , atunci calculati :
A) x+3y-3z
B)2x+5y-3z
C) (3x+6y)+(2y-6z)
D) (2x+4y)x (x+4y-6z)

Răspuns :

Pisicuta
x+3y-3z=x+2y+y-3z=17+4=21
2x+5y-3z=x+x+2y+2y+y-3z=17+17+4=38
3x+6y)+(2y-6z)=3(x+2y)+2(y-3z)=3*17+2*4=59
2x+4y)x(x+4y-6z)=2(x+2y)x(x+2y+2y-6z)=2*17x(17+2*4)=34x25=850

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