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LarisaAndra
a fost răspuns

Efectuati utilizand factorul comun:
a.14x12-14x7-5x13
b.7x49+7x31-7x50
c.32x25+32x11-36x30
d.99x11+13x11-112
e.177x36-177x31-77x5
f.32+32x15+32x84.

Răspuns :

a)=14(12-7)-5x13=4x5-5x13=5(4-13)=5x(-9)=-45

b)=7(49+31-50)=7x30=210

c)=32(25+11)-36x30=32x36-36x30=36(32-30)=36x2=72

d)=11(99+13-11)=11x101=1111

e)=177(36-31)-77x5=177x5-77x5=5(177-77)=5z100=500

f)=32(1+15+84)=32x100=3200
Brailanelu
a.14x (12-7-5x3) = 140
b. 7x(49+31+50) = 7x130=910
c. 32x(25+11)-36x30 =32x36-36x30
                                 32x0x30=0
d. 11x(99+13)-112 =11x(112-112) = 0
e. 177x(36-31-5)=117x0=0
f. 32+(15+84)=32+47=79
sper ca te-am ajutat :)

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