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a fost răspuns

Daaaauuuuuu Corooooannnnaa!
Determinati numarul real x din:
a)√6(2/√3+1/√2)+3√3=x-√50+6

Răspuns :

[tex]a)\sqrt6(\frac{2}{\sqrt3}+\frac{1}{\sqrt2})+3\sqrt3=x-\sqrt{50}+6\\ \sqrt6*\frac{2\sqrt2+\sqrt3}{\sqrt6}+3\sqrt3=x-5\sqrt2+6\\ 2\sqrt2+\sqrt3+3\sqrt3=x-5\sqrt2+6\\ 2\sqrt2+4\sqrt3=x-5\sqrt2+6\\ x=7\sqrt2+4\sqrt3+6[/tex]