Răspuns :
a. 8 = 2³ 12 = 2² · 3
cmmdc= 2² = 4
b. 49 = 7² 105 = 3· 5·7
cmmmdc= 7
c. 24 = 2² · 3 80 = 2⁴ · 5
cmmdc = 2² = 4
perechi de numere prime ( 4 ; 9 ) ; (4 ; 15 ) ; ( 9 ; 15) ; ( 9 ; 28 )
( 15 ; 28)
cmmdc= 2² = 4
b. 49 = 7² 105 = 3· 5·7
cmmmdc= 7
c. 24 = 2² · 3 80 = 2⁴ · 5
cmmdc = 2² = 4
perechi de numere prime ( 4 ; 9 ) ; (4 ; 15 ) ; ( 9 ; 15) ; ( 9 ; 28 )
( 15 ; 28)
a.8=2•2•2/12=2•2•3
c.m.m.d.c=2
b.49=7•7/105=3•5•7
c.m.m.d.c=7
c.24=2•2•2•3/80=2•2•2•2•5
c.m.m.d.c=2
(dindescompunere iei o singura data termenii comuni la exponentii cei mai mici)
c.m.m.d.c=2
b.49=7•7/105=3•5•7
c.m.m.d.c=7
c.24=2•2•2•3/80=2•2•2•2•5
c.m.m.d.c=2
(dindescompunere iei o singura data termenii comuni la exponentii cei mai mici)