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Georgiana10
a fost răspuns

Rezolvati in multimea numerelor intregi nenule inecuatiile: 3[2|2x+3|+4(x-8)+23]<4(x+9)+8x-21 | inseamna modul 

Răspuns :

Munmnc
I.
 explicitam modulul
3{2(-2x-3)+4x-32+23}<4x+36+8x-21
3(-4x-6+4x-32+23)<12x+15
3*(-15)<12x+15
-45<12x+15
12x>-60
x>-5
II
3[2(2x+3)+4x-32+23]<4x+36+8x-21
3[4x+6+4x-32+23]<12x+15
3(8x-26+23)<12x+15
24x-9<12x+15
12x<15+9
12x<24
x<2
6|2x+3|+12x-96+69<4x+36+8x-21

6|2x+3|<42

|2x+3|<7

-7<2x+3<7

-10<2x<4

-5<x<2

x∈(-5; 2)

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