👤
a fost răspuns

8^33÷(4^32×2^34+2^125÷2^27)=
Sa ma ajute cineva va rog

Răspuns :

Renatemambouko
8^33:(4^32×2^34+2^125:2^27)=
=2^99:(2^64×2^34+2^125:2^27)=
=2^99:(2^98+2^98)=
 =2^99:2^98(2^0+2^0)=
=2^99:2^98*2=
=2^99:2^99=1

Coco941
(2^3)^33:[(2^2)32×2^34+2^125:2^27]=2^99:(2^64×2^34+2^98)=2^99:(2^98+2^98)=1

Alte intrebari