ΔABC = dreptunghic in A
AB = 3, AC = 4 ⇒ CF. TEOREMEI PITAGORA
BC² = AB² + AC²
BC² = 3² + 4²
BC² = 9 + 16 = 25 ⇒ BC = √25
BC = 5
1) SIN B = AC / BC = 4 / 5
sin B = 4/ 5
2) SIN C = AB / BC = 3 / 5
sin C = 3/ 5
3) COS B = AB/ BC = 3 / 5
cos B = 3/ 5
4) COS C = AC / BC = 4/ 5
cos C = 4 / 5
5) tg B = AC / AB = 4 / 3
6) tg C = AB / AC = 3 / 4