Notam cu x si y lungimile catetelor. Au loc egalitatile:
[tex] \frac{x}{y} = \frac{5}{6} ;x+y+ \sqrt{x^2+y^2}=160 \\
y= \frac{6x}{5} [/tex] si inlocuind in cealalta ecuatie obtinem:
[tex]x= \frac{40}{3} \cdot(11-\sqrt{61}) \ si \ y=15 \cdot (11- \sqrt{61})[/tex]
