Răspuns :
6x²-x-1=10
Δ=b²-4ac
Δ=(-1)²-4×6×(-1)=1+24=25
X₁=-b+√Δ/ 2a
=1+5/12=6/12=1/2
X₂=-b-√Δ/2a
=1-5/12=-4/12=-1/3
Δ=b²-4ac
Δ=(-1)²-4×6×(-1)=1+24=25
X₁=-b+√Δ/ 2a
=1+5/12=6/12=1/2
X₂=-b-√Δ/2a
=1-5/12=-4/12=-1/3
[tex]6x^2-x-1=0\\
\Delta=1-(-1)*6*4\\
\Delta=1+24=25=\ \textgreater \ \sqrt\Delta}=5\\
x_{1,2}=\frac{1+-5}{12}\\
x_{1}=\frac{1+5}{12}=\frac{6}{12}=\frac{1}{2}\\
x_2=\frac{1-5}{12}=\frac{-4}{12}=\frac{-1}{3}.[/tex]