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(18*3^4)^2: (3^12 + 3^13)
Ajutati-ma va rog! Vreau rezolvarea completa si explicatii daca se poate. P.s. daca nu stiti "^" inseamna ridicat la putere.

Răspuns :

Flavistin
[tex]\frac{(18*3^{4})^{2}}{3^{12}+3^{13}}=\frac{(2*3^{2}*3^{4})^{2}}{3^{12}*(1+3)}=\frac{(2*3^{2+4})^{2}}{3^{12}*4}=\frac{(2*3^{6})^{2}}{3^{12}*4}=\frac{2^{2}*3^{6*2}}{3^{12}*4}=\frac{4*3^{12}}{3^{12}*4}=1[/tex]