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Camiavraam
a fost răspuns

se da f(x)=2x+3 calculati f(1)+f(2)+........+f(10)

Răspuns :

f(1)=5, f(2)=7, f(3)=9, f(4)=11,f(5)=13, f(6)=15 ,f(7)=17, f(8)=19, f(9)=21, f(10)=23. 5+7+9+11+13+15+17+19+21+23=140
Miky93
f(1)=2*1+3=2+3=5
f(2)=2*2+3=4+3=7
f(3)=2*3+3=6+3=9
................................
f(9)=2*9+3=18+3=21
f(10)=2*10+3=20+3=23

S=(5+23)*10/2

S=28*10/2

S=14*10

S=140

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