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Sebastianseby
a fost răspuns

Scrieti,folosind cat mai putine puteri.
a) 4 la puterea 2 * 2 la puterea 5 * 9 la puterea 2 * 16 la puterea 4 * 3 la puterea 7 * 27 la puterea 2

Răspuns :

(4²)x(2^5)x(9²)x(16^4)x(3^7)x(27²)=
(2²)²x(2^5)x(3²)²x(2^4)^4x(3^7)x(3³)²=
(2^4)x(2^5)x(3^4)x(2^16)x(3^7)x(3^6)=
(2^4)x(2^5)x(2^16)x(3^4)x(3^7)x(3^6)=
[2^(4+5+16)]x[3^(4+7+6)]=(2^25)x(3^17)

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