Răspuns :
inlocuieste in forula initiala: a+a+32+a/2=707 2a+a/2+32=707 4a+a+64/2=707 5a+64=1414 5a= 1350 a= 270 b= a+32=302 c= 270/2= 135
a+b+c=707
a+(a+32)+a/2=707
a+a+32+a/2=707
2a+a/2=675
4a+a=1350
5a=1350
a=270
b=a+32
b=270+32
b=302
c=a/2
c=270/2
c=135