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a+b+c=18 iar 2a+b+2c=25 calculati (a+c)x(3a+2b+3)

Răspuns :

Enekarina34
a+b+c=18
2a+b+2c=25
(a+c)(3a+2b+3c)=?  
a+b+c+2a+b+2c=18+25
3a+2b+3c=43
2a+b+2c-a-b-c=25-18
a+c=7
(a+c)(3a+2b+3c)=43*7=301

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