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Bubu98
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Calculeaza : Radical din 12/11 + 13/22+14/33+........110/1089 - ( 1+1/2+1/3+....+1/99)

Răspuns :

Renatemambouko
√[12/11 + 13/22+14/33+........110/1089 - ( 1+1/2+1/3+....+1/99) ]=
=√[(12/11-1)+(13/22-1/2)+(14/33-1/3)+....+(110/1089-1/99)]=
=√[(12-11)/11+(13-11)/22+(14-11)/33+....+(110-11)/1089]=
=√(1/11+2/22+3/33+....+99/1089)=
=√(1/11+1/11+1/11+....+1/11)=
=√(1/11 * 99)=
=√(99/11)=
=√9=3

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