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Calculati suma numerelor a si b stiind ca a² + b² - 4a+6b+13=0

Răspuns :

Miky93
a²-4a+4+b²+6b+9=0

(a-2)²+(b+3)²=0

a-2=0  ∧b+3=0
a=2      ∧b=-3

a+b=2-3=-1
Inteligent
a^2-4a+4+b^2+6b+9
(a-2)^2+(b+3)^2=0
a-2=0
a=2
b+3=0
b=-3
a+b= 2+(-3)
a+b=2-3
a+b=-1
Inteligent
a^2-4a+4+b^2+6b+9
(a-2)^2+(b+3)^2=0
a-2=0
a=2
b+3=0
b=-3
a+b= 2+(-3)
a+b=2-3
a+b=-1

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