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Vladpinzaru
a fost răspuns

ajutatima cu niste ecuatii ; a)3+x=28:4 b)5(x+2)=32 c)2a-3=17 d)120:z=12 e)8y+6=42-4 f)20+3t=100:2 va rog

Răspuns :

a) 3+x=7 => x=7-3=4 => x=4
b) 5x+10=32 => 5x=22 => x=22/5
c) 2a-3=17 => 2a=20 => a=10
d) 120/z=12 => z=120/12 => z=10
e) 8y+6=42-4 => 8y+6=38 => 8y=32 => y=4
f) 20+3t=100 => 20+3t=50 => 3t=30 => t=10

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