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Daca a,b,c sunt nr nat. Sa a+b+c=18
iar2a+b+2c=25.Calculati (a+c)×(3a+2b+3c)
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Răspuns :

2a+b+2c = 25   / +(a+b+c)  

3a+2b+3c = 25+(a+b+c)

si 

2a+b+2c = 25  / -(a+b+c)
a+c = 25 - (a+b+c )

=> (a+c)x(3a+2b+3c) = (25-18)x(25+18) = 7 x 43 = 301

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