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Un compus dibromurat cu NE=1 contine 86,02% brom, procente de masa. Determinati formula moleculara a compusului halogenat.

Răspuns :

Mirceavaman
Notam compusul: CxHyBr2
NE=1
1=[2+x(4-2)+y(1-2)+2(1-2)]/2=(2+2x-y-2)/2 => 2x-y=2 => y=2x-2
Mcompus..............100%
2*80g Br..............86,02%
Mcompus=160*100/86,02=186g/mol
MCxH2x-2Br2=12x+2x-2+160=186
14x-2+160=186 => 14x=28 => x=2
f.m: C2H2Br2

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