Răspuns :
sin deA = cateta opusa/ipotenuza=BC/AC -> AC=13 -> AB=12
cos deK=1/2-> masura unghiului NKM=30 co deK=NK/MK-> MK=14 ->MN=7v3
tg deE=0,6 =GF/EF-> GF=9/5 ->GE=3v34
ctg deR=2/3(dupa transformare)=QR/QP-> QR=8->RP=4v13
cos deK=1/2-> masura unghiului NKM=30 co deK=NK/MK-> MK=14 ->MN=7v3
tg deE=0,6 =GF/EF-> GF=9/5 ->GE=3v34
ctg deR=2/3(dupa transformare)=QR/QP-> QR=8->RP=4v13