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Efectuati:a) 5a⁶(-3b³)+(-2a²b)³;
b)(2,5xy²)(√2x)²-5x³y²;
c)6x²y²z+(-3xyz)(+2x)(-5y)+2z(-3xy)²
h)√2a*√6ab+2√3a²(-2b)+2ab√27a.

Răspuns :

DianaEllena
a) -15a⁶b³-2a⁶b³=-17a⁶b³

b)2,5xy² * 2x²-5x³y²=5x³y²-5x³y²=0

c)
6x²y²z+30x²y²z-18x²y²z=18x²y²z

h) √12a²b-4√3a²b+2ab*3√3a=
√12a²b-4√3a²b+6√3a²b=
√12a²b+2√3a²b=
2√3a²b+2√3a²b= 4√3a²b

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