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Biuta2003
a fost răspuns

cum fac : Aflati Z stiind ca :

a)Zxa+Zxb+Zxc=40 a+b+c=10

b) 4aZ+3bZ-2cZ=80 4a+3b-2c=16

c)a-3b=9 Z+3a-9b=31

Răspuns :

Nonim
a)z×a+z×b+z×c=40
z(a+b+c)=40
10z=40
z=40:10
z=4
b)4az+3bz-2cz=80
z(4a+3b-2z)=80
z×16=80
z=80:16
z=5
c)z+3a-9b=31
z+3(a+3b)=31
z+3×9=31
z+21=31
z=31-21
z=10