Răspuns :
a) 11x{ 3+5x [200-3x(442-400)]}+17= 11x{3+5x [200-3x42]+17= 11x[3+5x(200-126)+17= 11x(3+5x74)+17= 11x(3+370)+17= 11x373+17 = 4103+17=4120 b) 100+2x {2+2x[222-2x(2020-2000)]}= 100+2x[2+2x(222-2x20)]= 100+2x[2+2x(222-40)]= 100+2x(2+2x182)= 100+2x366= 100+732=832 a > b