Prima problema nu am inteles-o.
Problema 2.
[tex] \left \{ {{a-b = 5864} \atop {a+(a+b)=7b}} \right. => \left \{ {{a-b=5864} \atop {2a-6b=0}} \right. => \left \{ {{a-b=5864} \atop {a-3b=0}} \right.[/tex]
[tex]-b+3b = 5864 => b = 2932 => a = 5864 + 2932 = 8796[/tex]
Solutia S = { (8796 ; 2932) }
Problema 3.
Pai a = 1624, stiim din cerinta.
[tex] \left \{ {{\frac{1}{4}b = \frac{1}{4}c - 29} \atop {a + 3b + 2c = 4496}} \right. => \left \{ {{b=c-116} \atop {1624+3b+2c=4496}} \right. => 1624+3(c-116)+2c=4496[/tex]
[tex]=> 3(c-116)+2c=2872 => 5c = 2872 + 348 => c = 644 => b = c - 116 = 644 - 166 = 528 [/tex]
Solutia S = { (1624 ; 528 ; 644) }
Mult noroc,
Mexic
