👤
Unicubeu271
a fost răspuns

| (2-x)(x+2)+(x+3) la puterea a doua|=5

Răspuns :

[tex]\displaystyle |(2-x)(x+2)+(x+3)^2|=5 \\ |2x+4-x^2-2x+x^2+6x+9|=5 \\ |13+6x|=5 \\ 13+6x=5 \\ 6x=5-13 \\ 6x=-8 \\ x=- \frac{8}{6} \\ x=- \frac{4}{3} \\ 13+6x=-5 \\ 6x=-5-13 \\ 6x=-18 \\ x=- \frac{18}{6} \\ x=-3 [/tex]

Alte intrebari