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Osanuluka
a fost răspuns

x+y=8 si y+2z=35
a) 5x+13y+16z
b) 3y-2x+10z
c) 7x+10y+6z
d) 4(2z+y)+3x+3y

Răspuns :

Alex05ok
a) 5x+13y+16z=5x+5y+8y+16z=5(x+y)+8(y+2z)=5*8+8*35=320

b) 3y-2x+10z=-2x-2y+5y+10z=-2(x+y)+5(y+2z)=-2*8+5*35=159

c) 7x+10y+6z=7x+7y+3y+6z=7(x+y)+3(y+2z)=7*8+3*35=161

d) 4(2z+y)+3x+3y=4(y+2z)+3(x+y)=4*35+3*8=164

Diannatre
rezolvarea la a) este aceasta
Vezi imaginea Diannatre

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