Răspuns :
Prima problema e ff usoara: 30- ( 10 + 17 + 1 ) = 30 - 28 = 2 ( ii mai trebuie 2 timbre ).
A doua : matei are 15 ciorchini
mama lui = 5 +15 = 20
20 + 15 - 4 = 31
A doua : matei are 15 ciorchini
mama lui = 5 +15 = 20
20 + 15 - 4 = 31
30-(10+17+1)=30-28=2 timbre
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[15+(15+5)]-4=
(15+20)-4=
35-4=31 ciorchini
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[15+(15+5)]-4=
(15+20)-4=
35-4=31 ciorchini