Răspuns :
Deoarece masa de reactie e formata din hexaclorociclohexan si benzen nereactionat => 60% benzen
pornim de 100g amestec => 60g benzen nereactionat si 40g HCH
78g......3*35,5g....291g
C6H6 + 3Cl2 -> C6H6Cl6
x=?.......y=?...........40g
78g.........78g
C6H6 -> C6H6
60g.........60g
y=40*3*35,5/291=14,64g Cl2
x=40*78/291=10,72g benzen
mbenzentotala=70,72g
mbenzentotala:mCl2=70,72:14,64=4,83:1=4,83
pornim de 100g amestec => 60g benzen nereactionat si 40g HCH
78g......3*35,5g....291g
C6H6 + 3Cl2 -> C6H6Cl6
x=?.......y=?...........40g
78g.........78g
C6H6 -> C6H6
60g.........60g
y=40*3*35,5/291=14,64g Cl2
x=40*78/291=10,72g benzen
mbenzentotala=70,72g
mbenzentotala:mCl2=70,72:14,64=4,83:1=4,83