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Angelicaalbu
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Un compus dibromurat cu NE=1 contine 82,02 % brom, procente de masa. Determinati formula moleculara a compusului halogenat.

Răspuns :

Mirceavaman
Notam formula compusului: CxHyBr2
M.................100%
160g..............80%
M=160*100/80=200g/mol
M=12x+y+160=200 => 12x+y=40
NE=[2+x(4-2)+y(1-2)+2(1-2)]/2=1
2=2+2x-y-2 => 2x-y=2 => y=2x-2
12x+2x-2=40 => 14x=42 => x=3
y=2*3-2=4
f.m: C3H4Br2

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