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Se stie ca a=11 si b+c=8 .Calculati:
g) 11b+11c-6a;
h)3a-3b-3c;
i)11b+ac.
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Răspuns :

Renatemambouko
 a=11 si b+c=8 
g) 11b+11c-6a= 11(b+c)-6a=11*8-6*11=88-66=22
h)3a-3b-3c  =3a-3(b+c)=3*11-3*8=33-24=9
i)11b+ac =11b+11c=11(b+c)=11*8=88
a=11 b =4 ,c=4 4b+4c=8

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