Răspuns :
A+B+C+D=360
A/2=B/5=C/7=D/10=K=>A=2K
B=5K
C=7K
D=10K
24K=360=>K=15=> A=30 GRADE
B=75
C=105
D=150
PENTRU CEALATA PROBLEMA SUNT DOUA SITUATII
1) A=B=C SI A+B=160=> 2A=160=>A =80; B=80;C=80=> D=120
2)A=B=C SI A+D=160 => A+B+C+D=360 3A+D=360=> 2A+160=360 => 2A=200=> A=100, B=100, C=100, D=60
A/2=B/5=C/7=D/10=K=>A=2K
B=5K
C=7K
D=10K
24K=360=>K=15=> A=30 GRADE
B=75
C=105
D=150
PENTRU CEALATA PROBLEMA SUNT DOUA SITUATII
1) A=B=C SI A+B=160=> 2A=160=>A =80; B=80;C=80=> D=120
2)A=B=C SI A+D=160 => A+B+C+D=360 3A+D=360=> 2A+160=360 => 2A=200=> A=100, B=100, C=100, D=60