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AvramLorena259
a fost răspuns

Daca x+3y=2y+z=14 ,calculati :
x+5y+z =
3x+15y+3y=
5x+11y-2z=
5x+19y-2z=

Răspuns :

x+3y=14
2y+z=14

x+3y+2y+z=14+14=28

3x+15y+3z=3(x+5y+z)=3*28=84

5x+11y-2z = 5x + 15y - 4y - 2z = 5(x+3y)-2(2y+2) = 5*14 - 2*14 =3*14=42

5x+19y+2z = 5x+15y+4y+2z=5(x+3y)+2(2y+z)=5*14+2*14=7*14=98



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