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Andreeax33
a fost răspuns

[tex] \frac{2x+1}{6}- \frac{x-5}{4} = \frac{x+2}{8} [/tex]

Răspuns :

CarMina03
[tex] \frac{2x+1}{6} - \frac{x-5}{4} = \frac{x+2}{8} \\ \frac{8x+4}{24}- \frac{6x-30}{24} = \frac{3x+6}{24 } \\ 8x+4-6x+30=3x+6 \\ 2x+34=3x+6 \\ 34-6=3x-2x \\ x=28 [/tex]
[tex]\displaystyle \frac{2x+1}{6} - \frac{x-5}{4} = \frac{x+2}{8} \\ 4(2x+1)-6(x-5)=3(x+2) \\ 8x+4-6x+30=3x+6 \\ 8x-6x-3x=6-4-30 \\ -x=-28 \\ \boxed{x=28}[/tex]

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