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Izaaabellaaa
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Descompuneti in factori : (3x+1)(la a doua ) -(x+3)(la a doua) Vreau explicatie !

Răspuns :

[tex](3x+1)^2-(x+3)^2=[(3x+1)-(x+3)][(3x+1)+(x+3)]= \\ =(3x+1-x-3)(3x+1+x+3)=(2x-2)(4x+4)= \\ =8(x-1)(x+1)[/tex]

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