[tex] \frac{2x+1}{x+2} = \frac{2x+4-3}{x+2} = \frac{2(x+2)}{x+2} - \frac{3}{x+2} = 2 - \frac{3}{x+2} [/tex]
Deci 2x+1/x+2 ∈ Z <=> 2- 3/x+2 ∈ Z ( stim ca 2 ∈ Z) => - 3/x+2 ∈ Z => 3/x+2 ∈ Z =>
=> x+2 ∈ D₃ => x+2 ∈ { -3, -1, 1, 3 } => x ∈ { -5, -3, -1, 1}
