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DAU COROANA!
Calculati 1/2x+1/3x+1/6x-1/x,x apartine Q*

Răspuns :

   
[tex]\displaystyle \\ \frac{1}{2x}+ \frac{1}{3x}+ \frac{1}{6x}- \frac{1}{x}= \\ \\ = \frac{3}{6x}+ \frac{2}{6x}+ \frac{1}{6x}- \frac{6}{6x}= \\ \\ = \frac{3+2+1-6}{6x} = \frac{0}{6x}=\boxed{0}[/tex]



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