Răspuns :
[tex](2x-3)^2+(3x+2)^2=(2x)^2-2 \cdot 2x \cdot 3+3^2+(3x)^2+2 \cdot 3x \cdot 2+2^2= \\ =4x^2-12x+9+9x^2+12x+4=13x^2+13[/tex]
(2x -3)² = 4x² - 12x + 9
(3x+2)² = 9x² +12x + 4
suma lor=13x² +13 = 13(x²+1) .
(3x+2)² = 9x² +12x + 4
suma lor=13x² +13 = 13(x²+1) .