Răspuns :
3H2SO4+2Al=Al2(SO4)3+3H2↑
a)[tex]M_{AL}=27g/mol [/tex]
[tex]M_{Al2(SO4)3=54+96+192=342g/mol[/tex]
Notam sub Al2(SO4)3 necunoscuta x.
x=342*432/2*27=2736g Al2(SO4)3
b)[tex]M_{H2SO4}=2+32+64=98g/mol [/tex]
Notam sub H2SO4 necunoscuta y.
y=432*3*98/2*27=2352 g(md)
c=md/ms*100
49/100=2352/ms
ms=2352*100/49=4800 gH2SO4(ms)
c)[tex]M_{H2}=2g/mol[/tex]
Notam sub H2 necunoscuta z.
z=432*3*2/2*27
z=48 g H2
n=m/M
n=48/6=8 moli H2
1mol....22,4 L
8moli....x L
x=8*22,4=179,2 L
a)[tex]M_{AL}=27g/mol [/tex]
[tex]M_{Al2(SO4)3=54+96+192=342g/mol[/tex]
Notam sub Al2(SO4)3 necunoscuta x.
x=342*432/2*27=2736g Al2(SO4)3
b)[tex]M_{H2SO4}=2+32+64=98g/mol [/tex]
Notam sub H2SO4 necunoscuta y.
y=432*3*98/2*27=2352 g(md)
c=md/ms*100
49/100=2352/ms
ms=2352*100/49=4800 gH2SO4(ms)
c)[tex]M_{H2}=2g/mol[/tex]
Notam sub H2 necunoscuta z.
z=432*3*2/2*27
z=48 g H2
n=m/M
n=48/6=8 moli H2
1mol....22,4 L
8moli....x L
x=8*22,4=179,2 L