Răspuns :
A cerc = π[tex] R^{2} [/tex] [tex] \\ \\ Diametru = 6 \\ raza=3 \\ Acerc=π[tex] R^{2} [/tex]=> Acerc= 9π
diametrul = 2r =6 =>r=3 dm
aria disc= π [tex]r^{2} [/tex] = π [tex]3^{2} [/tex] = 9 π [tex] dm^{2} [/tex]
aria disc= π [tex]r^{2} [/tex] = π [tex]3^{2} [/tex] = 9 π [tex] dm^{2} [/tex]