A-----------------B
* *
* *
* *
D-------------------C
Cam asa arata paralelogramul tau
AD=8
deci si BC =8
Avem triunghiul dreptunghic BDC CU D=90° si C=30°
sin30=BD/BC
1/2=BD/8
BD=4
aplici T. Pitagora in acelasi triunghi
DC=²[tex] \sqrt{(BC)²-(BD)²} [/tex]
DC=[tex] \sqrt{64-16}[/tex]=4*[tex] \sqrt{3} [/tex]
PERIMETRRUL=2*8+2*4[tex] \sqrt{3} [/tex]=16+8[tex] \sqrt{3} [/tex]
