Răspuns :
a+b= 5 inmultim cu 3 3a+3b=15 (1)
b+c=7 inmultim cu 2 2b+2c=14 (2)
adunate (1) si (2)
3a+3b+2b+2c=3a+5b+2c=15+14=29
b+c=7 inmultim cu 2 2b+2c=14 (2)
adunate (1) si (2)
3a+3b+2b+2c=3a+5b+2c=15+14=29
a + b = 5 | ×3 ⇒ 3a + 3b = 15
b + c = 7 | ×2 ⇒ 2b + 2c = 14
3a + 5b +2c = 29
b + c = 7 | ×2 ⇒ 2b + 2c = 14
3a + 5b +2c = 29