x+y= 2,(4)
x-y=1 => x=1+y am scris x in functie de y si inlolcuim in prima relatie
1+y + y =2,(4)
1+ 2y= [tex]2 \frac{4}{9} [/tex]
2y= [tex]2 \frac{4}{9} - 1[/tex]
2y = [tex] [tex]\frac{22}{9}[/tex] -1
2y = [tex] [tex]\frac{22}{9} - \frac{9}{9} [/tex]
2y = [tex] \frac{13}{9} [/tex]
y= [tex] \frac{13}{9} :2[/tex]
y= [tex] \frac{13}{9}* \frac{1}{2} [/tex]
y= [tex] \frac{13}{18} [/tex]
x=[tex]1+\frac{13}{18}= \frac{18}{18} + \frac{13}{18}= \frac{31}{18} [/tex]
