Răspuns :
[tex]3+ \sqrt{2}- \frac{12}{ \sqrt{2} }= \\
3+ \sqrt{2}- \frac{12 \sqrt{2} }{2}= \\
3+ \sqrt{2}-6 \sqrt{2}=3-5 \sqrt{2} [/tex]
[tex]3+ \sqrt{2}-6 \sqrt{2}=
3+ \sqrt{2} - 6 \sqrt{2}=
3-5 \sqrt{2} [/tex]
