👤
a fost răspuns

x+y=-2√3
x²-y²=4√6
x-y=?

Răspuns :

[tex]\displaystyle x+y=-2 \sqrt{3} \\ x^2-y^2=4 \sqrt{6} \\ x-y=? \\ x^2-y^2=4 \sqrt{6} \\ (x+y)(x-y)=4 \sqrt{6} \\ -2 \sqrt{3} (x-y)=4 \sqrt{6} \\ x-y=- \frac{4 \sqrt{6} } {2 \sqrt{3} } \\ x-y=-2 \sqrt{2} [/tex]

Alte intrebari