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Laurstefan14
a fost răspuns

Va rog ajutati-ma!Descompuneti in factori:
a)(3x+5)²-(x+1)²
b)(x+√2)²-8
c)(2x+√3)²-27
d)(√2x-1)²-32x²
e)x²-2√3x+3-(y-2√3)²
f)14a-49a²+100b²-1
..va rog mult dau best! ajutati-ma!!!! nu ani am puncte ca as fi pus mai multe va rog sa ma ajutati

Răspuns :

Renatemambouko
a)(3x+5)²-(x+1)²=(3x+5-x-1)(3x+5+x+1)=(2x+4)(4x+6)=4(2x+2)(2x+3)
b)(x+√2)²-8 =(x+√2-2√2)(x+√2+2√2) =(x-√3)(x+3√3)
c)(2x+√3)²-27=(2x+√3-3√3)(2x+√3+3√3)=(2x-2√3)(2x+4√3)=4(x-√3)(x+2√3)
d)(√2x-1)²-32x²=(√2x-1-4√2x)(√2x-1+4√2x)=(-3√2x-1)(6√2x-1)
e)x²-2√3x+3-(y-2√3)²=(x-√3)²-(y-2√3)²=(x-√3+y-2√3)(x-√3-y+2√3)=(x+y-3√3)(x-y+√3)
f)14a-49a²+100b²-1  =100b²-(49a²-14a+1)=100b²-(7a-1)²=(10b+7a-1)(10b-7a+1)

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